Question

Find the roots of the quadratics equation $3x^2-4\sqrt{3}x+4=0$.

Answer 1

$3x^2-4\sqrt{3}x+4=0$

$3x^2-2\sqrt{3}x-2\sqrt{3}x+4=0$

$\sqrt{3}(\sqrt{3}x-2)-2(\sqrt{3}x-2)=0$

$(\sqrt{3}x-2)(\sqrt{3}x-2)=0$

$(\sqrt{3}x-2{)}^2=0$

So $x=\frac{2}{\sqrt{3}}$

Roots $=\frac{2}{\sqrt{3}},\frac{2}{\sqrt{3}}$.