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Question

Find the second order derivatives of each of the following functions :
log(logx)

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Solution

Let y=log(logx). Then,
dydx=1logxddx(logx)=1xlogx=(xlogx)1
d2ydx2=ddx{(xlogx)1}
d2ydx2=(xlogx)2ddx(xlogx)=1(xlogx)2(1+logx)=(1+logx)(xlogx)2

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