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Question

Find the shortest distance and the equation of the line corresponding to the shortest distance between the lines.
r=(3i+8j+k)+λ(3ij+k)
r=(3i7j+6k)+μ(3i2j+4k)

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Solution

x33=yB1=z31=γ1p(3r,+3,Br1,r1+3)l2:x+33=y+72=z61=γ2Q=(33r2,7+2r2,6+4r2)QP:(3r1+3r2+6,r2r2+15,r14r23)So,3(3r1+3r2+6)(r12r2+15)+(r14r23)=0Similarly,7r1+11r2=0......(2)from(1)and(2)r1=r2=0PQ=(6,15,3)Shortestdistance=(33)2+(7Q)2+(63)2=330directionratioofline(2,5,1)So,equationofline,x32=y85=z31


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