Find the shortest distance and the vector equation of the line of shortest distance between the lines given by: →r=(3i+8j+3k)+λ(3i−j+k) →r=(−3i−7j+6k)+μ(−3i+2j+4k)
A
3√30 units
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B
√90 units
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C
2√30 units
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D
3√10 units
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Solution
The correct option is A3√30 units We have →a1=3^i+8^j+3^k→b1=3^i−^j+^k →a2=−3^i−7^j+6^k and →b2=−3^i+2^j+4^k Now, b1×b2=∣∣
∣
∣∣^i^j^k3−11−324∣∣
∣
∣∣=−6^i−15^j+3^k
∣b1×b2∣=√62+152+32=3√30 a1−a2=6^i+15^j−3^k Therefore shortest distance between the given lines is