Question

Find the simplest form of :

$\left(i\right)\frac{69}{92}\left(ii\right)\frac{473}{645}\left(iii\right)\frac{1095}{1168}\left(iv\right)\frac{368}{496}$

Answer 1

Sol:

(i) Prime factorization of 69 and 92 is:

69 = 3 x 23

92 = 2^2 x 23

Therefore, 69/92= 3X23/2^2X23= 3/2^2= 3/4

Thus, simplest form is 3/4

(ii) Prime factorization of 473 and 645 is:

473 = 11 x 43

645 = 3 x 5 x 43

Therefore, =11X43/3X5X43= 11/15

Thus, simplest form is 11/15

(iii) Prime factorization of 1095 and 1168 is:

1095=3 x 5 x 73

1168=24x73

Therefore, 1095/1168= 15/16

Thus, simplest form is 15716

(iv) Prime factorization of 368 and 496 is:

368 = 24 x 23

496 = 24 x 31

Therefore, 368/496= 24X23/24X31
thus, simplest form is 23/31