Question

The simplest form of $\frac{1095}{1168}$ is

$\left(a\right)\frac{17}{26}\left(b\right)\frac{25}{26}\left(c\right)\frac{13}{16}\left(d\right)\frac{15}{16}$

Answer 1

List out all the prime factors of both numbers in product form.
$\frac{1095}{1168}$ = $\frac{5\times 3\times 73}{2\times 2\times 2\times 2\times 73}$

After cancelling 73 you get $\frac{15}{16}$