Question

Find the slope of segment $QR$, which is a side of square $PQRS$( as shown in the figure above )

• A. $-\frac{10}{3}$
• B. $-\frac{7}{3}$
• C. $-\frac{4}{3}$
• D. $\frac{3}{7}$
• E. $\frac{7}{3}$

Answer 1

The correct option is B $-\frac{7}{3}$

Given points are $P(0,7),Q(7,10)$ and $PQRS$ is a square.

Slope of line $PQ$ is $\frac{(10-7)}{(7-0)}=\frac{3}{7}$
The line $QR$ is perpendicular to $QP$.
Therefore, the slope of $QR$ is $-\frac{7}{3}$.