Question

Find the slope of tangent to the curve $y=3x^2-6$ at the point on it whose $x-$coordinate is $2.$

Answer 1

$y=3x^2-6$

Differentiating both sides w.r.t. x, we get,

$\frac{dy}{dx}=6x$

At $x=2$, slope of tangent

$[\frac{dy}{dx}{]}_{x=2}=6(2)=12$