Question

Find the slope of tangent to the curve $y=3x^2-6$ at the point on it whose x-coordinate is 2.

Answer 1

$y=3x^2-6$

Differentiating both sides, we get,

$\frac{dy}{dx}=6x$

At x=2, slope of tangent = $6\left(2\right)=12$

Therefore, required slope = 12