Question

Find the slope of the line joining the points $(2a,3b)$ and $(a,-b)$.

Answer 1

We know that the slope of the line joining two points $(x_1,y_1)$ and $(x_2,y_2)$ is:

$m=\frac{y_2-y_1}{x_2-x_1}$

Here, the given points are $(2a,3b)$ and $(a,-b)$, therefore, the slope of the line is:

$m=\frac{y_2-y_1}{x_2-x_1}=\frac{-b-3b}{a-2a}=\frac{-4b}{-a}=\frac{4b}{a}$

Hence, the slope of the line is$\frac{4b}{a}$.