Find the slope of the line z1-i-z1-i-2-0A- 1B- 2C- -1D- -2

The correct option is C 1 Let z = (x + i y) (x + i y) (1 i) + (x i y) (1 + i) + 2 = 0 x + y + i(y x) + (x + y) + i (x y) + 2 = 0 2(x + y) + 2 = 0 x ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Mathematics

Cartesian Plane

Find the slop...

Question

Find the slope of the line z(1 - i) + z(1 + i) + 2 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

-1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

-2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
-1

Let z = (x + i y)

(x + i y) (1 - i) + (x - i y) (1 + i) + 2 = 0

x + y + i(y - x) + (x + y) + i (x - y) + 2 = 0

2(x + y) + 2 = 0

x + y + 1 = 0

Slope = -1

Suggest Corrections

Similar questions

Reflection of the complex number $\frac{2 - i}{3 + i}$ in the straight line $z (1 + i)$ = $¯ z (i - 1)$ is

Q. If

z_{1} = 2 - i, z_{2} = 1 + i

, find

∣ ∣ ∣ \frac{z_{1} + z_{2} + 1}{z_{1} + z_{2} + i} ∣ ∣ ∣

Q. The slope of the line

| z 1 | = | z + i |

If | $\frac{z_{1} - 2 z_{2}}{2 - z_{1}_{2}}$ | = 1, | $z_{2}$ | $\neq$ 1, then | $z_{1}$ | =

$I f z_{1} = 2 - i, z_{2} = - 2 + i, find (i) R e (\frac{z_{1} z_{2}}{z_{1}}) (i i) I m (\frac{1}{z_{1} z_{2}})$

Join BYJU'S Learning Program

Find the slope of the line z(1 - i) + z(1 + i) + 2 = 0

The correct option is B -1 Let z = (x + i y) (x + i y) (1 - i) + (x - i y) (1 + i) + 2 = 0 x + y + i(y - x) + (x + y) + i (x - y) + 2 = 0 2(x + y) + 2 = 0 x + y + 1 = 0 Slope = -1

The correct option is B
-1

Let z = (x + i y)

(x + i y) (1 - i) + (x - i y) (1 + i) + 2 = 0

x + y + i(y - x) + (x + y) + i (x - y) + 2 = 0

2(x + y) + 2 = 0

x + y + 1 = 0

Slope = -1