Question

Find the smallest number which, on being decreased by $3$, is completely divisible by $18,36,32$ and $27.$

Answer 1

Step: Find the smallest number

$L.C.M.$ of $18,36,32$ and $27$

$\therefore L.C.M.=2\times 2\times 2\times 2\times 2\times 3\times 3\times 3=864$
$\therefore$ Smallest number $=864+3=867$
Hence, the smallest number is $867.$