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Question

Find the solution of following equation
2tanθcotθ+1=0 then tanθ=mn and tanθ=p then m+n+p =

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Solution

Put cotθ as 1tanθ
2tanθ1tanθ+1=0
put tanθ=x
2x2+x1=0x=12,1
tanθ=1θ=3π4
tanθ=12θ=tan112

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