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Question

Find the solution of the following equations . Also , verify your answer .

x5-6=115x .


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Solution

Given , the linear equation is x5-6=115x-------1

x5-115x=6

3x-x15=6

2x15=6

2x=6×15

2x=90

x=902

x=45

So, the required solution of given equation is x=45 .

Check :- Putting x=45 in the equation 1, we get

LHS =455-6

=9-6

RHS =4515

=3

Since, LHS = RHS = 3

Hence, solution x=45 is satisfy the given equation .


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