Question

Find the solution of the given equation:
$\frac{[9x-(3+4x\left)\right]}{[2x-(7-5x\left)\right]}=\frac{6}{7}$

Answer 1

$\frac{9x-(3+4x)}{2x-(7-5x)}=\frac{6}{7}$

$⟹\frac{9x-3-4x}{2x-7+5x}=\frac{6}{7}$

$⟹\frac{5x-3}{7x-7}=\frac{6}{7}$

$⟹\frac{5x-3}{7(x-1)}=\frac{6}{7}$

$⟹\frac{5x-3}{x-1}=6$

$⟹5x-3=6x-6$

$⟹x=3$