Find the solution of the given pair of equations
2x+3y=9, 3x+4y=5
Given,
2x+3y=9 ...(1)
3x+4y=5 ...(2)
Multiply equation (1) with 3
6x+9y=27 ...(3)
Multiply equation (2) with 2
6x+8y=10 ...(4)
Subtracting (4) from (3):
y=17
Substituting y=17 in (1), we get
2x+3(17)=9
⇒2x=9−51=−42⇒.x=−422=−21
∴x=−21,y=17