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Question

Find the solution of the inequation 0 < |x-3| 1 contains the interval.


A

x [-2, 4]

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B

x (2, 4)

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C

x [2, 4]

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D

x (-2, 4)

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Solution

The correct option is A

x [-2, 4]


0 < |x-3| 1

|x-3| is always positive, it can reverse less than zero. Minimum value x - 3 can take -1

-1 x - 3 1

-2 x 4

Above inequality contains the interval

x [-2, 4]


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