Find the solution to the following system of linear equations:
2x-y+6=0
4x+5y-16=0

(2, -3)

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(2, 3)

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(-1, 4)

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(1, 4)

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Solution

The correct option is C
(-1, 4)

2x-y+6=0…..(I)

4x+5y-16=0…(II)

From the equation I we get,

y=6+2x

Substituting this value of y in equation II we get,

4x+[5(6+2x)]-16=0

14x+14=0

x=-1

Substituting this value of x in equation I we get,

2(-1)-y+6=0

⇒4-y=0

⇒y=4

Hence the solution is (-1, 4)

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