Find the species / elemental atom has minimum number of unpaired electrons

K r^{+}

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M n^{2 +}

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F e^{3 +}

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O^{+}

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Solution

The correct option is A $K r^{+}$
$K r^{+} \to 4 s^{2} 4 p^{5} 1 u n p a i r e d e^{-}$
$M n^{2 +} \Rightarrow 3 d^{5} 4 s^{0} 5 u n p a i r e d e^{-}$
$F e^{3 +} \Rightarrow 3 d^{5} 4 s^{0} 5 u n p a i r e d e^{-}$
$O^{+} \Rightarrow 2 s^{2} 2 p^{3} 3 u n p a i r e d e^{-}$

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