Find the square of $2 a + b$

4 a^{2} + 4 a b + b^{2}

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a^{2} + a b + b^{3}

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4 a^{2} + a b + b^{2}

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4 a^{2} + 4 a b - b^{2}

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Solution

The correct option is A $4 a^{2} + 4 a b + b^{2}$
Squaring,
$(2 a + b)^{2}$
$= (2 a)^{2} + 2 (2 a) (b) + (b^{2})$
$= 4 a^{2} + 4 a b + b^{2}$

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Similar questions

(2 a + b)^{2} = 4 a^{2} + b^{2} + 4 a b

4 a^{2} + 4 a b + b^{2} =

State True or False:

On subtracting $a^{2} + a b + b^{2}$ from $4 a^{2} - 3 a b + 2 b^{2}$ , the answer is $3 a^{2} - 4 a b + b^{2}$ .

8 a^{3} - b^{3} - 4 a x + 2 b x

Factorise: $4 a^{2} + 4 a b + b^{2}$

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