Question

Find the square of the following numbers
(i) $32$
(ii) $35$
(iii) $86$
(iv)$93$
(v) $71$
(vi) $46$

Answer 1

(i) ${32}^2=(30+2)(30+2)$

$=900+60+60+4$

$=1024$

(ii) ${35}^2=(30+5)(30+5)$

$=900+150+150+25$

$=1225$

(iii) ${86}^2=(80+6)(80+6)$

$=6400+480+480+36$

$=7396$

(iv) ${93}^2=(90+3)(90+3)$

$=8100+270+270+9$

$=8649$

(v)${71}^2=(70+1)(70+1)$

$=4900+140+1$

$=5041$

(vi) ${46}^2=(40+6)(40+6)$

$=1600+480+36$

$=2080+36$

$=2116$.