Question

Find the square root of the following numbers by the factorisation numbers : 34596

Answer 1

Resolving $34596$ as the product of primes, we get

$\Rightarrow 34596=2^2\times 3^2\times {31}^2$

$\Rightarrow \sqrt{34596}=\sqrt{2^2\times 3^2\times {31}^2}=2\times 3\times 31$

$\therefore \sqrt{34596}=186$