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Question

Find the squares of:

(i) 31, (ii) 72; (iii) 37; (iv) 166.

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Solution

(i) (a + b)2 = a2 + 2ab + b2

∴312 = (30 + 1)2 = 302 + 2 × 30 × 1 + 12 = 900 + 60 + 1 = 961

(ii) (a + b)2 = a2 + 2ab + b2

∴722 = (70 + 2)2 = 4900 + 280 + 4 = 5184

(iii) (a + b)2 = a2 + 2ab + b2

∴372 = (30 + 7)2 = 900 + 420 + 49 = 1369

(iv) (a + b)2 = a2 + 2ab + b2

∴1662 = (160 + 6)2 = 25600 + 1920 + 36 = 27556


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