Find the squares of the algebraic expressions given below:

(i) 2x − 3y

(ii) x − 2

(iii) 2x − 1

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Solution

We know that (x − y)² = x² + y² − 2xy

(i)

Square of 2x − 3y = (2x − 3y)²

= (2x)² + (3y)²− 2 × 2x × 3y

= 4x² + 9y²− 12xy

(ii)

Square of x − 2 = (x − 2)²

= x² + 2² − 2 × x × 2

= x² + 4 − 4x

(iii)

Square of 2x − 1 = (2x − 1)²

= (2x)² + (i)² − 2 × 2x × 1

= 4x² + 1 − 4x

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Similar questions

Find the squares of the following algebraic expressions

(i) 2x + 3y

(ii) x + 2

(iii) 2x + 1

Find the square of :

(i) $x + 3 y$

(ii) $2 x - 5 y$

(iii) $a + \frac{1}{5 a}$

(iv) $2 a - \frac{1}{a}$

(v) $x - 2 y + 1$

(vi) $3 a - 2 b - 5 c$

(vii) $2 x + \frac{1}{x} + 1$

(viii) $5 - x + \frac{2}{x}$

(ix) $2 x - 3 y + z$

(x) $x + \frac{1}{x} - 1$

$2 x$ and $(\frac{- 1}{2})$ are ___ of the algebraic expression $(2 x - \frac{1}{2})$ .

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