Question

Find the squares of the following numbers
(i) $\frac{3}{8}$ (ii) $\frac{7}{10}$ (iii) $\frac{1}{5}$ (iv) $\frac{2}{3}$ (v) $\frac{31}{40}$

Answer 1

(i) $3/8$

$(3/8{)}^2=3/8\times 3/8=(3\times 3\left)/\right(8\times 8)=9/64$

(ii) $7/10$

$(7/10{)}^2=7/10\times 7/10=(7\times 7\left)/\right(10\times 10)=49/100$

(iii) $1/5$

$(1/5{)}^2=1/5\times 1/5=(1\times 1\left)/\right(5\times 5)=1/25$

(iv) $2/3$

$(2/3{)}^2=2/3\times 2/3=(2\times 2\left)/\right(3\times 3)=4/9$

(v) $31/40$

$(31/40{)}^2=31/40\times 31/40=(31\times 31\left)/\right(40\times 40)=961/1600$