Question

Find the stopping distance of each car. Stopping distance of car with 72 km/h speed.

Answer 1

$2a{S}_1=v^2-u^{2}2(-5)$
$S_1=0(-\frac{700}{36})2$
So, $S_1=37.8m$
Stopping distance of car with 60 km/h speed.
$2(-5)S_2=0-\left(\frac{600}{36}\right)2$
So, $S_2=27.77m$.
$S_1+S_2=65.57m$