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Question

Find the strength of 500 mL of a 1 M glucose solution.

A
90 g/L
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B
45 g/L
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C
180 g/L
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D
135 g/L
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Solution

The correct option is C 180 g/L
Molarity = number of molestotal volume (mL)×1000
1=number of moles500×1000
Number of moles = 0.5
Mass of glucose = 0.5 mol × 180 g/mol = 90 g

Strength=mass of solutevolume of solution (L)=900.5=180 g/L
So, the strength of glucose will be = 180 g/L

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