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Question

Find the suitable value of A so that:
34 > 3A

A
A = 1
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B
A = 3
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C
A = 5
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D
A = 2
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Solution

The correct option is C A = 5
We know that for fractions with a common numerator but different denominators, the fraction with a lower denominator is the one greater in value.

By putting value of A = 1, we get,
34 < 31
By putting value of A = 3, we get,
34 < 33
By putting value of A = 2, we get,
34 < 32

Only by putting value of A = 5, we get,
34 > 35

∴ The required value of A = 5.


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