Find the sum and product of zeroes of polynomials $2 x^{2} - 8 x + 6$ .

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Solution

$2 x^{2} - 8 x + 6 = 0$
$⟹ 2 x^{2} - 2 x - 6 x + 6 = 0$
$⟹ 2 x (x - 1) - 6 (x - 1) = 0$
$⟹ x = 1$ or $3$
So $1, 3$ are the zeroes of polynomial $2 x^{2} - 8 x + 6$
Sum of zeroes is $1 + 3 = 4$
Product of zeroes is $1 (3) = 3$

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