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Question

Find the sum of all even integers between 100 and 550 , which are divisible by 9.

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Solution

The series follows as below,

108,117,...........,549

Clearly,

a=108

d=117108=9

an=a+(n1)d

549=108+(n1)9

441=9(n1)

49=n1

n=50

Therefore there are 50 numbers

Sn=n2[a+l]

S50=502[108+549]

=25[657]

=16425

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