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Question

Find the sum of all natural numbers between 100 and 200 which are divisible by 4.

A
24552
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B
3600
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C
2357
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D
2112
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Solution

The correct option is A 3600
The numbers between 100 and 200 which are divisible by 4 are 104,108,112,...,196.
This is an AP with first term a=104, common difference d=4 and last term l=196.
Let there be n terms in this AP. Then,
an=196a+(n1)d
196=104+(n1)×4
n=24
Required sum =Sn=n2[a+l]=242[104+196]=3600

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