Find the sum of co-ordinates of the point which divides the join of the points (2, 4) and (6, 8) externally in the ratio 5 : 3.
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Solution
The required coordinates of the point which divides the join (2, 4) and (6, 8) externally in the ratio 5 : 3, are (mx2−nx1m−n,my2−ny1m−n) Here m:n=5:3,(x1,y1)=(2,4)(x2,y2)=(6,8) Hence the required co-ordinates =(12,14)