Find the sum of interior angles of a polygon with $12$ sides in degrees.
$1800^{\circ}$
$1200^{\circ}$
$1500^{\circ}$
$1400^{\circ}$

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Solution

The correct option is A: $1800^{\circ}$
Sum of interior angles of a polygon with $n$ sides $= (n - 2) \times 180^{\circ}$

$∴$ Sum of interior angles of a polygon with $12$ sides $= (12 - 2) \times 180^{\circ}$

$= 10 (180^{\circ})$

$= 1800^{\circ}$

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Find the sum of interior angles of a polygon with 12 sides in degrees.1800∘1200∘1500∘1400∘

The correct option is A: 1800∘Sum of interior angles of a polygon with n sides =(n−2)×180∘ ∴ Sum of interior angles of a polygon with 12 sides =(12−2)×180∘ =10(180∘) =1800∘

Find the sum of interior angles of a polygon with $12$ sides in degrees.
$1800^{\circ}$
$1200^{\circ}$
$1500^{\circ}$
$1400^{\circ}$

The correct option is A: $1800^{\circ}$
Sum of interior angles of a polygon with $n$ sides $= (n - 2) \times 180^{\circ}$

$∴$ Sum of interior angles of a polygon with $12$ sides $= (12 - 2) \times 180^{\circ}$

$= 10 (180^{\circ})$

$= 1800^{\circ}$