The sum of interior angles of a polygon with 12 sides is___

$1080^{\circ}$

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$1600^{\circ}$

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$1800^{\circ}$

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$1900^{\circ}$

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Solution

The correct option is D
$1800^{\circ}$

Sum of interior angles of a polygon $= (n - 2) \times 180^{\circ}$

$∴$ Sum of interior angles of a polygon with 12 sides $= (12 - 2) \times 180^{\circ}$

$= 10 (180^{\circ})$

$= 1800^{\circ}$

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The sum of interior angles of a polygon with 12 sides is___

The correct option is D 1800∘ Sum of interior angles of a polygon =(n−2)×180∘ ∴ Sum of interior angles of a polygon with 12 sides =(12−2)×180∘ =10(180∘) =1800∘

The correct option is D
$1800^{\circ}$

Sum of interior angles of a polygon $= (n - 2) \times 180^{\circ}$

$∴$ Sum of interior angles of a polygon with 12 sides $= (12 - 2) \times 180^{\circ}$

$= 10 (180^{\circ})$

$= 1800^{\circ}$