Find the sum of remainder obtained when 64, 65 and 66 are divided by 7.

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Solution

The correct option is C 6
$64 \div 7 \Rightarrow$ Remainder is $1$
$65 \div 7 \Rightarrow$ Remainder is $2$
$66 \div 7 \Rightarrow$ Remainder is $3$
Hence, required sum is $= 1 + 2 + 3 = 6$

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