find the sum of the cubes of first three multiples of 3

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Solution

Dear student,

$T h e f i r s t t h r e e m u l t i p l e s o f 3 a r e 3, 6, 9 S u m o f c u b e s o f 3, 6, 9 = 3^{3} + 6^{3} + 9^{3} = 27 + 216 + 729 = 972$

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