Question

Find the sum of the lengths of the bases of a trapezium whose area is 4.2 m² and whose height is 280 cm.

Answer 1

$$\begin{gathered} \text{Given:} \\ {\text{Area of the trapezium = 4.2 m}}^2 \\ \text{Height = 280 cm =}\frac{280}{100}\text{m = 2.8 m} \\ \mathrm{Area}\mathrm{of}\mathrm{trapezium}=\frac{1}{2}\times (Sum\mathrm{of}\mathrm{the}\mathrm{parallel}\text{b}\mathrm{ases)\times (}\text{Height}) \\ \text{4.2 =}\frac{1}{2}\text{×(Sum of the parallel bases)×2.8} \\ 4.2\times 2=(Sum\; of\mathrm{the}\mathrm{parallel\; bases)\times 2.8} \\ \mathrm{Sum\; of}\mathrm{the}\mathrm{parallel\; bases}=\frac{8.4}{2.8}=3\text{m} \end{gathered}$$