Question

Find the sum of the series $3+5+7+9+...+59$.

• A. $899$
• B. $799$
• C. $699$
• D. $599$

Answer 1

The correct option is A $899$

Clearly above series is in AP with first term $3$ and common difference $2$

So general term will be $3+(n-1)2=59$ , since last term is given

$\Rightarrow 2n=58\Rightarrow n=29$

Hence required sum $=\frac{n}{2}(2a+(n-1\left)d\right)=\frac{29}{2}(6+28\times 2)=899$