Find the sum of the series $3 + 5 + 7 + 9 + . . . + 59$ .

899

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799

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699

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599

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Solution

The correct option is A $899$
Clearly above series is in AP with first term $3$ and common difference $2$
So general term will be $3 + (n - 1) 2 = 59$ , since last term is given
$\Rightarrow 2 n = 58 \Rightarrow n = 29$
Hence required sum $= \frac{n}{2} (2 a + (n - 1) d) = \frac{29}{2} (6 + 28 \times 2) = 899$

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400

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