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Question

Find the sum of the squares of the first 9 natural numbers.


A

185

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B

385

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C

285

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D

485

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Solution

The correct option is C

285


The first 9 natural numbers are 1,2,3,... and 9.

The sum of the squares of the first n natural numbers is given by

Sn=12+22+...+n2=n(n+1)(2n+1)6.

Therefore, the sum of the squares of the first 9 natural numbers is given by

Sn=12+22+...+82+92

=9(9+1)(2×9+1)6

=9×10×196

=285

Thus, the sum of the squares of the first 9 natural numbers is 285.


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