Question

Find the surface area of a cube whose volume is $?$

$\left(ii\right)$ $216d{m}^3$

Answer 1

Given: Volume of cube$=216d{m}^3$

We know that,

Volume of cube $=(\text{Side}{)}^3$

$\Rightarrow 216=(\text{Side}{)}^3$

$\Rightarrow \text{Side}=\sqrt[3]{3216}$

$=6dm$

$\therefore$ Surface area of cube $=6\times (\text{side}{)}^2$

$=6\times (6{)}^2$

$=6\times 36$

$=2196d{m}^2$

Hence, the surface area of cube is $216d{m}^2.$