Question

Find the surface area of a sphere, if its volume is 38808 cubic cm.($\mathrm{\pi }=\frac{22}{7}$)

Answer 1

Let the radius of the sphere be r cm.

Volume of the sphere = 38808 cm³

$$\begin{gathered} \therefore \frac{4}{3}\mathrm{\pi }{r}^3=38808{\mathrm{cm}}^3 \\ \Rightarrow \frac{4}{3}\times \frac{22}{7}\times r^3=38808 \\ \Rightarrow r^3=\frac{38808\times 21}{88}=9261 \\ \Rightarrow r^3={\left(21\right)}^3 \\ \Rightarrow r=21\mathrm{cm} \end{gathered}$$
∴ Surface area of the sphere = 4$\mathrm{\pi }$r² = $4\times \frac{22}{7}\times {\left(21\mathrm{cm}\right)}^2$ = 5544 cm²

Thus, the surface area of the sphere is 5544 cm².