Find the surface area of the cuboidal box which is open at the top- if-l-length of the cuboid- b - breadth of the cuboid andh -height of the cuboidA- Surface Area -2 lb - bh - lh B- Surface Area -2 lb -2 bh - hlC- Surface Area - lb -2 bh -2 hlD- Surface Area -2 lb - bh -2 hl

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Surface area of a solid

Find the surf...

Question

Find the surface area of the cuboidal box which is open at the top, if:
l=length of the cuboid,
b=breadth of the cuboid and
h=height of the cuboid

Surface Area = 2(lb+bh+lh)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Surface Area = 2lb+2bh+hl

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Surface Area = lb+2bh+2hl

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Surface Area = 2lb+bh+2hl

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C Surface Area = lb+2bh+2hl

When the cuboidal box is cut open, the total surface area is the sum of the areas of 5 rectangles as shown in the figure.
Surface Area = hl+lb+bh+hl+bh
$∴$ Surface Area = lb+2bh+2hl

Suggest Corrections

Similar questions

What is the surface area of the cuboidal box which is open at the top, if:
$l =$ length of the cuboid,
$b =$ breadth of the cuboid and
$h =$ height of the cuboid

Q. Applying the idea we just learned, Find the surface area of the cuboidal box which is open at the top, if:
l=length of the cuboid,
b=breadth of the cuboid and
h=height of the cuboid

The surface area of a box which is in the form of a cuboid whose dimensions are l $\times$ b $\times$ h is:

The surface area of a box, which is in the shape of a cuboid, and whose dimensions are $l \times b \times h$ is__________.

Q. Total surface area of a cuboid of length l, breadth b and height h is

2 (l b + b h + l h)

Join BYJU'S Learning Program

Find the surface area of the cuboidal box which is open at the top, if: l=length of the cuboid, b=breadth of the cuboid and h=height of the cuboid

The correct option is C Surface Area = lb+2bh+2hl When the cuboidal box is cut open, the total surface area is the sum of the areas of 5 rectangles as shown in the figure. Surface Area = hl+lb+bh+hl+bh ∴ Surface Area = lb+2bh+2hl

Find the surface area of the cuboidal box which is open at the top, if:
l=length of the cuboid,
b=breadth of the cuboid and
h=height of the cuboid

The correct option is C Surface Area = lb+2bh+2hl

When the cuboidal box is cut open, the total surface area is the sum of the areas of 5 rectangles as shown in the figure.
Surface Area = hl+lb+bh+hl+bh
$∴$ Surface Area = lb+2bh+2hl