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Standard XIII

Chemistry

Van der Waal's Forces

Find the temp...

Question

Find the temperature ( $in K$ ) at which 3 moles of $S O_{2}$ will occupy a volume of $10 L$ at a pressure of $15 atm$ .
[ $a = 6.71 {atm litre}^{2} {mol}^{- 2}$ ; $b = 0.0564 {litre mol}^{- 1}$ ]

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Solution

van der Waal equation is:
$(P + \frac{a n^{2}}{V^{2}}) (V - n b) = n R T$
Given: $P = 15 a t m$
$V = 10 L$ , $n = 3$ , $a = 6.71 {atm litre}^{2} {mol}^{- 2}$
$(15 + \frac{6.71 \times 9}{100}) (10 - 3 \times 0.0564) = 3 \times 0.082 \times T$
on solving we get :
$T = 624 K$

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Similar questions

Q. Find the temperature (

in K

) at which 3 moles of

S O_{2}

will occupy a volume of

10 L

at a pressure of

15 atm

.
[

a = 6.71 {atm litre}^{2} {mol}^{- 2}

;

b = 0.0564 {litre mol}^{- 1}

]

Q. Find the temperature (

in K

) at which 3 moles of

S O_{2}

will occupy a volume of

10 L

at a pressure of

15 atm

.
[

a = 6.71 {atm litre}^{2} {mol}^{- 2}

;

b = 0.0564 {litre mol}^{- 1}

]

Q. Find the temperature at which

3

moles of

S O_{2}

will occupy a volume of

10

litre at a pressure of

15 a t m

a = 6.71 a t m l i t r e^{2} m o l^{- 2}; b = 0.0564 l i t r e m o l^{- 1}

Q. How many moles of

S O_{2}

will occupy a volume of

10

litre at a pressure of

15 a t m

and temperature

624 K

(a = 6.71 a t m L^{2} m o l^{- 2}; b = 0.0564 l i t r e m o l^{- 1})

Q. Calculate from the van der Waal's equation, the temperature (in K) at which

102

g of

S O_{2}

would occupy a volume of

10 d m^{3}

15

atm pressure. ( Answer = [T], where [.] is greatest integer function)

[

a = 6.7 a t m L^{2} m o l^{2}, b = 0.0564 L m o l^{- 1}

]

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Van der Waal's Forces

Standard XIII Chemistry

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Find the temperature (in K) at which 3 moles of SO2 will occupy a volume of 10 L at a pressure of 15 atm. [ a=6.71 atm litre2 mol−2; b=0.0564 litre mol−1]

van der Waal equation is: (P+an2V2)(V−nb)=nRT Given: P=15 atm V=10 L, n=3, a=6.71 atm litre2 mol−2 (15+6.71×9100)(10−3×0.0564)=3×0.082×T on solving we get : T=624 K

Find the temperature ( $in K$ ) at which 3 moles of $S O_{2}$ will occupy a volume of $10 L$ at a pressure of $15 atm$ .
[ $a = 6.71 {atm litre}^{2} {mol}^{- 2}$ ; $b = 0.0564 {litre mol}^{- 1}$ ]

van der Waal equation is:
$(P + \frac{a n^{2}}{V^{2}}) (V - n b) = n R T$
Given: $P = 15 a t m$
$V = 10 L$ , $n = 3$ , $a = 6.71 {atm litre}^{2} {mol}^{- 2}$
$(15 + \frac{6.71 \times 9}{100}) (10 - 3 \times 0.0564) = 3 \times 0.082 \times T$
on solving we get :
$T = 624 K$