Find the tension T1 in the string. All surfaces are smooth.
A
30N
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B
40N
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C
50N
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D
60N
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Solution
The correct option is C50N The FBDs of the masses are as shown
Let the direction of the acceleration be as shown in the figure
So, from the FBDs we have, T2=3a............(i)
And, T1−T2=2a.................(ii)
From eq (i) & (ii) we have T1=5a.............(iii)
Also, 100−T1=5a............(iv) ∴ from eq (iii) & (iv) we have 100=10a⟹a=10m/s2
Thus, T1=5a⟹T1=5×10=50N
Alternate:
Acceleration of the system is given by, a=Supporting ForceTotal mass=10010=10m/s2
From the FBD of 5Kg, we have 100−T1=5a T1=100−5(10)=50N