Find the thermo emf developed in a Cu-Ag thermocouple when the junctions are kept at 0oC and 40oC- - for Cu and Ag is 2-76 and 2-5 - V- oC and - for both Cu and Ag is 0-012 - V- oC2

The correct option is A 10.4 μ V E =αθ So, α =α #160;_ cu α #160;_ ag α =(2.76 2.50)× 10 ^ 6 =0.26× 40× 10 ^ 6 β =0 θ =40 0 ...

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Standard XII

Mathematics

Parametric Form of Tangent: Hyperbola

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Question

Find the thermo emf developed in a Cu-Ag thermocouple when the junctions are kept at $0^{o} C$ and $40^{o} C$ . $α$ for Cu and Ag is 2.76 and 2.5 $μ V /^{o} C$ and $β$ for both Cu and Ag is 0.012 $μ V / (^{o} C)^{2}$

1.04

μ V

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10.4

μ V

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210.4

μ V

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none of these

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Solution

The correct option is A 10.4 $μ V$
$E = △ α △ θ S o, α = α_{c u} - α_{a g} α = (2.76 - 2.50) \times 10^{- 6} = 0.26 \times 40 \times 10^{- 6} β = 0 △ θ = 40 - 0 = 40 E = 10.4 μ V$

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Find the thermo emf developed in a Cu-Ag thermocouple when the junctions are kept at 0oC and 40oC. α for Cu and Ag is 2.76 and 2.5 μV/oC and β for both Cu and Ag is 0.012 μV/(oC)2

The correct option is A 10.4 μVE=△α△θSo, α=αcu−αagα=(2.76−2.50)×10−6=0.26×40×10−6β=0△θ=40−0=40E=10.4μV

Find the thermo emf developed in a Cu-Ag thermocouple when the junctions are kept at $0^{o} C$ and $40^{o} C$ . $α$ for Cu and Ag is 2.76 and 2.5 $μ V /^{o} C$ and $β$ for both Cu and Ag is 0.012 $μ V / (^{o} C)^{2}$

The correct option is A 10.4 $μ V$
$E = △ α △ θ S o, α = α_{c u} - α_{a g} α = (2.76 - 2.50) \times 10^{- 6} = 0.26 \times 40 \times 10^{- 6} β = 0 △ θ = 40 - 0 = 40 E = 10.4 μ V$