Say:
The 1st hint is the number in tens place \(= 40\)
So, the digit in tens place is \(4.\)
The 2nd hint is that the digit at hundreds place is \(2\) less than the digit at tens place.
So, the digit at hundreds place is \(2~ (2\) less than \(4 = 2)\)
The 3rd hint is that the digit at ones place is \(4\) more than the digit at hundreds place.
So, the digit at ones place is \(6~ (4\) more than \(2 = 6)\)
Let us calculate the answer.
Step:
So, number of envelopes in hundreds place \(= 2\) hundreds \(= 200\)
Number of envelopes in ones place \(= 6\) ones \(= 6\)
Total number of envelopes \(= 200 + 40 + 6 = 246\)
Hence, there are \(246\) envelopes, and option B is the correct answer.