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Question

Find the unit vector along ab, where a=^i+3^j^k and b=3^i+2^j+^k.

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Solution

a=^i+3^j^k,b=3^i+2^j+^k
ab=2^i+^j2^k
Unit vector along ab=ab|ab|
|ab|=(2)2+12+(2)2=3
Unit vector along ab is 2^i+^j2^k3=23^i+13^j+23^k
Hence, the unit vector is 23^i+13^j23^k

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