If a-k- b-2-2k- c-2-k- find a unit vectors normal to the vectors a-b- and b-c-

The correct option is B #160;î 2ĵ + 6k̂√(41) a⃗ + nbsp;b⃗ = 3ĵ + k̂ b⃗ + nbsp;c⃗ = nbsp; 2î + 4ĵ + k̂ Since we need a unit vector pe ...

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Vector Addition

If a⃗=î+ĵ-k...

Question

If $\to a =^i +^j -^k, \to b = -^i + 2^j + 2^k$ & $\to c = -^i + 2^j -^k$ , find a unit vectors normal to the vectors $\to a + \to b$ and $\to b + \to c$ .

\frac{-^i - 2^j + 6^k}{\sqrt{40}}

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\frac{-^i - 2^j + 6^k}{\sqrt{41}}

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\frac{^i - 2^j + 6^k}{\sqrt{41}}

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\frac{-^i + 2^j + 6^k}{\sqrt{41}}

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Solution

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Similar questions

\to a =^i +^j -^k, \to b = -^i + 2^j +^k

\to c = -^i + 2^i -^k . A

\to a + \to b

\to b + \to c

\to a = 2^i +^j + 3^k

\to b = 3^i + 2^j +^k

\to c =^i -^j - 4^k

\to d =^i + 2^j -^k

(\to a \times \to b) \times (\to c \times \to d) =

\to a =^i +^j, \to b =^j +^k, \to c = α \to a + β \to b

^i - 2^j +^k, 3^i + 2^j -^k, \to c

\frac{α}{β} =

\to a = 3^i + 2^j + 2^k, \to b = -^i + 3^j -^k, \to c =^i +^j +^k

\to a \times (\to b \times \to c)

(\to a \times \to b) \times \to c

\to a = 3^i - 2^j +^k,

\to b = 2^i - 4^j - 3^k, \to c = -^i + 2^j + 2^k

\to a + \to b + \to c = 4^i - 4^j

\to a =^i -^j + 2^k, \to b = 2^i + 3^j +^k, \to c =^i -^k

\to a + 2 \to b - 3 \to c

\sqrt{78}

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