Find the unknown value: $11 + . . . = 13 + 11$

13

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11

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3

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24

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Solution

The correct option is A $13$
Whole numbers are commutative under addition. i.e. $a + b = b + a$ . Therefore, $11 + 13 = 13 + 11$ .

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24 - b = 13

11

The value of $s i n (s i n^{- 1} \frac{1}{3} + s e c^{- 1} 3) + c o s (t a n^{- 1} \frac{1}{2} + t a n^{- 1} 2)$ is

∣ ∣ ∣ ∣ \begin{matrix} 10! & 11! & 12! 11! & 12! & 13! 12! & 13! & 14! \end{matrix} ∣ ∣ ∣ ∣

x

\frac{4}{3} \times [x + \frac{1}{13}] = \frac{4}{3} \times \frac{8}{11} + \frac{4}{3} \times \frac{1}{13} .

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