Question

Find the upper limit of the median class from the given frequency distribution table.

Class	$0-5$	$6-11$	$12-17$	$18-23$	$24-29$
Frequency	$03$	$10$	$15$	$8$	$11$

• A. $17$
• B. $17.5$
• C. $18$
• D. $18.5$

Answer 1

The correct option is A $17$

Cumulative frequency =Sum of all frequency $N=47$

Class	Frequency	CF
0-5 6-11 12-17 18-23 24-29	3 10 15 8 11	3 13 28 36 47

$N=47,\frac{N}{2}=23.5$

Since $23.5$ lies in CF $28$

So, $12-17$ is median class

Thus upper limit of median class $=17$